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如何从一个php文件向另一个地址post数据,不用表单和隐藏的变量的

发布时间:2007-03-06 作者: 来源:转载
可以使用以下函数来实现:--------------------------------------------------------------------------------------------------也可以这样

可以使用以下函数来实现:

functionposttohost($url,$data){
$url=parse_url($url);
if(!$url)return"couldn'tparseurl";
if(!isset($url['port'])){$url['port']="";}
if(!isset($url['query'])){$url['query']="";}

$encoded="";

while(list($k,$v)=each($data)){
$encoded.=($encoded?"&":"");
$encoded.=rawurlencode($k)."=".rawurlencode($v);
}

$fp=fsockopen($url['host'],$url['port']?$url['port']:80);
if(!$fp)return"Failedtoopensocketto$url[host]";

fputs($fp,sprintf("POST%s%s%sHTTP/1.0n",$url['path'],$url['query']?"?":"",$url['query']));
fputs($fp,"Host:$url[host]n");
fputs($fp,"Content-type:application/x-www-form-urlencodedn");
fputs($fp,"Content-length:".strlen($encoded)."n");
fputs($fp,"Connection:closenn");

fputs($fp,"$encodedn");

$line=fgets($fp,1024);
if(!eregi("^HTTP/1..200",$line))return;

$results="";$inheader=1;
while(!feof($fp)){
$line=fgets($fp,1024);
if($inheader&&($line=="n"||$line=="rn")){
$inheader=0;
}
elseif(!$inheader){
$results.=$line;
}
}
fclose($fp);

return$results;
}
?>
--------------------------------------------------------------------------------------------------
也可以这样

$URL="www.mysite.com/test.php";
$ch=curl_init();
curl_setopt($ch,CURLOPT_URL,"https://$URL");
curl_setopt($ch,CURLOPT_POST,1);
curl_setopt($ch,CURLOPT_POSTFIELDS,"Data1=blah&Data2=blah");
curl_exec($ch);
curl_close($ch);
?>


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