判“新”函数：得到今天与明天的秒数

函数源代码：

---------------------------------------------

说明：若$varTime在今天的范围内，返回ture,否则返回false.

function bTodayToTomorrow($varTime)

{

$nowYear=date("Y");

$nowMonth=date("n");

$nowDay=date("j");

$aryTodayAndTomorrow["Today"]=date("U",mktime(0,0,0,$nowMonth,$nowDay,$nowYear));

$aryTodayAndTomorrow["Tomorrow"]=date("U",mktime(0,0,0,$nowMonth,($nowDay+1),$nowYear));

if($varTime>=$aryTodayAndTomorrow["Today"]&&$varTime<$aryTodayAndTomorrow["Tomorrow"])

{

return true;

}

else

{

return false;

}

}

------------------

类似的你可以进行任意时间段的判断。